A.ABC has.A = 40°.b = 4, and a = 3.
I've drawn one possible version of this triangle below. Could there be a second solution? (yes/no).
If so, sketch a different triangle with these same values. Make obtuse angles look clearly obtuse and acute angles clearly acute. Make the side length of 4 look longer than the side length of 3.
Note: There is no reason to actually solve the triangle. Simply make a sketch of what it would look like if there were a second solution. Include only the numbers 40, 4 and 3 in your diagram.