Answer:
Explanation:Hello again Alessia, i hope the explanation i give helps you so to determine the limiting reactant, we need to calculate the amount of product that can be formed from each reactant and then choose the reactant that produces the least amount of product. The balanced chemical equation for the reaction between CuCl₂ and NaNO3 is: 2 CuCl₂ + 2 NaNO3 → Cu2(NO3)2 + 2 NaCl The molar mass of CuCl₂ is 134.45 g/mol, so 8 grams of CuCl₂ is equal to: 8 g / 134.45 g/mol = 0.0595 mol CuCl₂ The molar mass of NaNO3 is 84.99 g/mol, so 9 grams of NaNO3 is equal to: 9 g / 84.99 g/mol = 0.106 mol NaNO3 Using stoichiometry and the balanced chemical equation, we can calculate the amount of product that can be formed from each reactant: From 0.0595 mol of CuCl₂: 0.0298 mol of Cu2(NO3)2 can be formed From 0.106 mol of NaNO3: 0.053 mol of Cu2(NO3)2 can be formed Therefore, the limiting reactant is CuCl₂ because it produces the least amount of product (0.0298 mol of Cu2(NO3)2). Always welcome :)