Question

In a certain Algebra 2 class of 29 students, 13 of them play basketball and 14 of them play baseball. There are 11 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

Answer 1

We can use the formula:

P(A and B) = P(A) + P(B) - P(A or B)

where A represents playing basketball, B represents playing baseball, and P(A or B) represents the probability of playing at least one of the sports.

From the given information, we can calculate:

P(A) = 13/29
P(B) = 14/29
P(A or B) = 1 - P(neither) = 1 - 11/29 = 18/29

Substituting these values into the formula, we get:

P(A and B) = 13/29 + 14/29 - 18/29
P(A and B) = 9/29

Therefore, the probability that a student chosen randomly from the class plays both basketball and baseball is 9/29.