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Prove that C2 with a square of length 10x+1 with x being 0

User Symbiotech
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To prove anything about a shape or object, we need to define what we mean by "C2 with a square of length 10x+1".

Assuming that C2 is a circle with a circumference of 2, and x is equal to 0, then the square with a length of 10x+1 would have a length of 1.

In this case, the statement to prove would be: "The circle C2 with a square of length 1 (circumscribed around the circle) has an area greater than or equal to the area of the circle."

To prove this statement, we can use the formula for the area of a circle (A = πr^2), where r is the radius of the circle. We know that the circumference of C2 is 2, so we can find the radius using the formula for the circumference of a circle (C = 2πr):

2 = 2πr
r = 1/π

Substituting this value of r into the formula for the area of a circle, we get:

A = π(1/π)^2
A = 1/π

Therefore, the area of C2 is 1/π.

Next, we need to find the area of the square with a length of 1. The formula for the area of a square is A = s^2, where s is the length of a side. In this case, the length of a side is 1, so the area of the square is:

A = 1^2
A = 1

Comparing the area of the circle and the area of the square, we have:

1/π ≥ 1

Since π is approximately 3.14, we can see that 1/π is greater than 1. Therefore, the circle C2 with a square of length 1 (circumscribed around the circle) has an area greater than the area of the square.

Therefore, we have proven that C2 with a square of length 10x+1 (where x is 0) has a circle with an area greater than the area of the square.
User Musonda
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