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Find the two values that x can have it 5x2+41=86

1 Answer

6 votes
Answer is x= 3, x = -3

Step by step

Given

5x^2 + 41 = 86

Subtract 41 from both sides to isolate exponent

5x^2 + 41 - 41 = 86 - 41
Simplify

5x^2 = 45

Divide both sides by 5

5/5 x^2 = 45/5

x^2 = 9

Take square root of both sides

√x^2 = +- √9

x = + - 3

x = 3, x = -3
User Javier De La Cueva
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