Question

Evaluate and simplify the expression
when x = 3 and y = -3.
2(3x + xy) - 4y² + x² = [?]

Answer 1

When x = 3 and y = -3, we can substitute these values into the expression:

2(3x + xy) - 4y² + x²

= 2(3(3) + (3)(-3)) - 4(-3)² + 3² [Substitute x = 3 and y = -3]

= 2(9 - 9) - 4(9) + 9

= -36 + 9

= -27

Therefore, the value of the expression when x = 3 and y = -3 is -27.

Answer 2

• -27

Explanation:

2(3x + xy) - 4y² + x², when x =3 and y = -3

Substitute x with 3 and y into -3:-

`\mathrm{2\left(3* \:3+3\left(-3\right)\right)-4\left(-3\right)^2+3^2}`

Follow PEMDAS the order of operations:-

Calculate within the parentheses:-

• 
  `\mathrm{\left(3*\:3+3\left(-3\right)\right)}\bf =0`

• 
  `\mathrm{2*\:0-4\left(-3\right)^2+3^2}`

Now, calculate the exponents:-

• 
  `\mathrm{3^2=\bf 9}`

• 
  `\mathrm{2*\:0-4*\:9+9}`

Multiply :-

• 
  `\mathrm{2* 0 }\bf = 0`
• 
  `\mathrm{0-4*\:9+9}`
• 
  `\mathrm{4 * 9}\bf =36`

• 
  `\mathrm{0-36+9}`

Add and subtract:-

• 
  `\mathrm{0-36+9}}`
• 
  `\mathrm{0-36=\bf {-36}}`
• 
  `\mathrm{-36+9}`

• 
  `\mathrm{-36+9}\bf = -27`

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Hope this helps!