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In 1992, Ukrainian Sergei Bubka used a short pole to jump to a height of 6.13 m. If the maximum potential energy associated with Bubka was 4800 kJ at the midpoint of his jump, what was his mass?

User Tlegrand
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2 Answers

4 votes
It’s is 5 good job in your test tho good luck
User Richeym
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Answer:

The answer to your problem is, 79.8 kJ

Step-by-step explanation:

Mass can be experimentally defined as a measure of the body's inertia, meaning the resistance to acceleration (change of velocity) when a net force is applied.

h=6.13 meters
mg=9.81 m/s2

PEg = 480 x
10^(3J)

We will use the equation for gravitational potential energy, and rearrange it to solve for mass:

Therefore PEg = mgh

mass = PEg / gh

mass = 4.80 ×
10^(3) / 9.81 x 6.13

mass = 79.8 kJ

Thus the answer to your problem is, 79.8 kJ

User Cecilio Pardo
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