Question

What is the pressure in atm of a 5.00 L tank with 4.80 moles of oxygen at 39.3 °C?

Answer 1

Step-by-step explanation:

Ideal gas law

PV = n R T P = ? V = 5.00 L n = 4.80 moles T = 312.45 K

R = gas constant = .082057 l atm /(K mol)

P 5.00 = 4.80 * .082057 * 312.45

P = 24.6 atm