Question

an animal shelter has fixed weekly expenses of 750. each animal in the shelter cost an additional 6 a week. during the winter month, the weekly expenses are at the most 900. write and solve an inequality that represents the number of animal at the shelter for expenses to be at the most 900 a week

Answer 1

Let's use "x" to represent the number of animals in the shelter.

The fixed weekly expenses of the animal shelter are $750, and each animal costs an additional $6 per week. Therefore, the total weekly expenses of the animal shelter would be:

Total Weekly Expenses = Fixed Weekly Expenses + (Cost Per Animal * Number of Animals)

Total Weekly Expenses = 750 + 6x

We know that during the winter month, the weekly expenses are at most $900. So we can write the following inequality to represent this situation:

Total Weekly Expenses ≤ 900

Substituting the expression for the total weekly expenses, we get:

750 + 6x ≤ 900

Simplifying this inequality, we get:

6x ≤ 150

Dividing both sides by 6, we get:

x ≤ 25

Therefore, the inequality that represents the number of animals in the shelter for expenses to be at most $900 a week is:

x ≤ 25

This means that the shelter can have at most 25 animals during the winter month for the expenses to be within the limit of $900 a week.