Answer:
x = - 1, 6
Explanation:
the denominator of h(x) cannot be zero as this would make h(x) undefined
equating the denominator to zero and solving gives the values of x that cannot be in the domain of h(x)
x² - 5x - 6 = 0
(x + 1)(x - 6) = 0
equate each factor to zero and solve for x
x + 1 = 0 ⇒ x = - 1
x - 6 = 0 ⇒ x = 6
then x = - 1, 6 are values not in the domain of h(x)