Question

Find
Midpoint
Slop
Distance
Line equation

Answer 1

Line equation is the correct answer

Answer 2

Explanation:

midpoint
`=((x_1+x_2)/(2) ,(y_1+y_2)/(2))`

`=((3+7)/(2) ,(1+5)/(2))`

`=(5,3)`

slope
`=(y_2-y_1)/(x_2-x_1)`

`=(5-1)/(7-3)`

`=(4)/(4)`

`=1`

distance
`=√((x_2-x_1)^2+(y_2-y_1)^2)`

`=√((7-3)^2+(5-1)^2)`

`=√(4^2+4^2)`

`=√(16+16)`

`=√(32)`

`=√(16*2)`

`=4√(2)`

Line equation:

`y-y_1=m(x-x_1)` (this is the point- gradient form)

`y-1=1(x-3)` (m=1 is slope, and I used point (3,1) for
`(x_1,y_1)` )

`y-1=x-3`

`y=x-2`