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For the function p = 2 - 3q². what is the instantaneous rate of change function?​

User Rfedorov
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Answer:

Explanation:

To find the instantaneous rate of change function for the given function p = 2 - 3q², we need to find the derivative of the function with respect to q. The derivative gives us the slope of the tangent line to the curve at any point, which is the instantaneous rate of change at that point.

So, we can start by taking the derivative of the given function:

dp/dq = d/dq(2 - 3q²)

dp/dq = 0 - 3(2q)

dp/dq = -6q

Therefore, the instantaneous rate of change function for p = 2 - 3q² is given by:

dp/dq = -6q

This means that the instantaneous rate of change (slope of the tangent line) of the function p with respect to q is -6q at any given point.

User Ngoc Nguyen
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