Answer:
1301.14 g
Step-by-step explanation:
If an iron ore sample is 35.00% Fe by mass, it means that 100 g of the sample contains 35.00 g of Fe.
To calculate how many grams of ore are needed to obtain 454.0 g of Fe, we can use the proportion:
(g of ore) / (100 g of ore) = (454.0 g of Fe) / (35.00 g of Fe)
Solving for (g of ore), we get:
(g of ore) = (100 g of ore) x (454.0 g of Fe) / (35.00 g of Fe)
(g of ore) = 1301.14 g
Therefore, 1301.14 g of the iron ore sample is needed to obtain 454.0 g of Fe.