Answer:
We can use the binomial distribution formula to calculate the probabilities in this scenario. The formula is:
P(X = k) = (n choose k) * p^k * (1 - p)^(n - k)
where:
P(X = k) is the probability of getting k successes
n is the total number of trials
p is the probability of success in each trial
(n choose k) is the binomial coefficient, which can be calculated as n! / (k! * (n - k)!)
(a) Out of five adults, none is concerned that employers are monitoring phone calls.
Here, k = 0 (zero successes), n = 5, and p = 0.49 (the probability of success).
Using the binomial distribution formula:
P(X = 0) = (5 choose 0) * 0.49^0 * (1 - 0.49)^(5 - 0) = 0.105
So the probability of none of the five adults being concerned is 0.105, or approximately 0.105.
(b) Out of five adults, all are concerned that employers are monitoring phone calls.
Here, k = 5 (all successes), n = 5, and p = 0.49.
Using the binomial distribution formula:
P(X = 5) = (5 choose 5) * 0.49^5 * (1 - 0.49)^(5 - 5) = 0.013
So the probability of all five adults being concerned is 0.013, or approximately 0.013.
(c) Out of five adults, exactly three are concerned that employers are monitoring phone calls.
Here, k = 3, n = 5, and p = 0.49.
Using the binomial distribution formula:
P(X = 3) = (5 choose 3) * 0.49^3 * (1 - 0.49)^(5 - 3) = 0.270
So the probability of exactly three adults being concerned is 0.270, or approximately 0.270.