Question

Leila wrote an equation to represent the revenue of a parking lot for one day. She let x represent the number of cars that paid to park and y represent the number of trucks that paid to park. If a car costs $8 per day, a truck costs $10 per day, and the total revenue for the day was $830, which equation could Leila use to represent the number of cars and trucks that paid to park that day?

8 x + 10 y = 1,660
10 x + 8 y = 1,660
8 x + 10 y = 830
10 x + 8 y = 830

Answer 1

8x + 10y = 830

Explanation:

Leila can use the equation 8x + 10y = 830 to represent the number of cars and trucks that paid to park that day.

Since x represents the number of cars and they cost $8 each, the total revenue from cars is 8x. Similarly, y represents the number of trucks and they cost $10 each, so the total revenue from trucks is 10y.

The total revenue for the day is given as $830, so the equation becomes:

8x + 10y = 830

Answer 2

Leila can use the following equation to represent the number of cars and trucks that paid to park that day:

8x + 10y = 830

In this equation, x represents the number of cars that paid to park, and y represents the number of trucks that paid to park.

The equation takes into account that each car costs $8 per day, and each truck costs $10 per day. The total revenue for the day was $830.

To calculate the total revenue, Leila needs to multiply the number of cars by the cost per car and add it to the number of trucks multiplied by the cost per truck. This gives the equation:

Revenue = 8x + 10y

And since the total revenue for the day was $830, she can set the equation equal to 830:

8x + 10y = 830

Therefore, the correct answer is:

8x + 10y = 830