Question

Which line has a y-intercept of 2 and an x-intercept of -3? A diagonal curve rises through (negative 5, negative 1 point 2), (negative 5, negative 0 point 5), (negative 2, 0 point 9), (0, 2), (2, 3 point 2), (3, 4) and (4, 4 point 8) on the x y coordinate plane. W. A diagonal curve rises through (negative 3, negative 4), (negative 2, negative 3 point 1), (0, negative 2), (1, negative 1 point 2), (3, 0) and (4, 0 point 8) on the x y coordinate plane. X. A diagonal curve rises through (negative 4, negative 3), (negative 3, negative 1 point 5), (negative 2, 0), (negative 1, 1 point 5), (0, 3) and (1, 4 point 5) on the x y coordinate plane. Y. A diagonal curve rises through (negative 1, negative 4 point 5), (0, negative 3), (1, negative 1 point 5), (2, 0), (3, 1 point 5) and (4, 3) on the x y coordinate plane. Z. A. W B. X C. Y D. Z Reset Next © 2023 Edmentum. All rights reserved.

Answer 1

The equation of the line with a y-intercept of 2 and an x-intercept of -3 can be written in slope-intercept form as: y = mx + b, where m is the slope and b is the y-intercept.

The y-intercept is given as 2, so b = 2.

To find the slope, we can use the formula:

m = (y2 - y1) / (x2 - x1)

Using the x-intercept (-3, 0) and the y-intercept (0, 2), we get:

m = (2 - 0) / (0 - (-3)) = 2/3

So the equation of the line is: y = (2/3)x + 2.

None of the given options match this equation, so the answer is none of the above.

Explanation: