Question

Which relationship has a zero slope? A two column table with five rows. The first column, x, has the entries, negative 3, negative 1, 1, 3. The second column, y, has the entries, 2, 2, 2, 2. A two column table with five rows. The first column, x, has the entries, negative 3, negative 1, 1, 3. The second column, y, has the entries, 3, 1, negative 1, negative 3. A coordinate plane with a straight line starting at (negative 5, negative 5) and passing through the origin, and ending at (5, 5) A coordinate plane with a straight line starting at (negative 2, 5) and passing the x-axis at (negative 2, 0), and ending at (negative 2, 5).

Answer 1

The slope of the first line is 0, as per slope-intercept form.

What is the slope of a straight line?

The linear equation
`y = mx + c` represents the slope-intercept form of a line passing through the point
`(x, y)`.

Here, 'm' is the slope and 'c' is the y-intercept of the given line.

The slope of a line that passes through points
`(x_1, y_1)` and
`(x_2, y_2)` is defined as:

`m = ((y_2-y_1))/((x_2-x_1))`

Here, the slope of the first line that passes through
`(- 3, 2)` and
`(-1, 2)` is

`= ((2-2))/([- 1 - (- 3)])`

`= (0)/(2)`

`= 0`

Now, the slope of the second line that passes through
`(- 3, 3)` and
`(-1, 1)` is

`=((1-3))/([- 1 - (- 3)])`

`= (-2)/(2)`

`= - 1`