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A 23.6g sample of an unknown gas occupies a volume of 12.0L at standard temperature and pressure. What is the molecular mass of this gas.

User Joe Pitz
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2 Answers

7 votes

Answer:

Step-by-step explanation:

44.08 g/mol.

User Anjoe
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Answer:The molecular mass (molar mass) of this gas is equal to 44.08 g/mol.

Given the following data:

Mass = 23.6 grams

Volume = 12.0 Liters

Standard temperature = 273 K

Standard pressure = 1 atm.

To calculate the molecular mass (molar mass) of this gas, we would use the ideal gas law equation;

WherThe molecular mass (molar mass) of this gas is equal to 44.08 g/mol.

Given the following data:

Mass = 23.6 grams

Volume = 12.0 Liters

Standard temperature = 273 K

Standard pressure = 1 atm.

To calculate the molecular mass (molar mass) of this gas, we would use the ideal gas law equation.

Step-by-step explanation:

Mass = 23.6 grams

Volume = 12.0 Liters

Standard temperature = 273 K

Standard pressure = 1 atm.

User Bhautik Ziniya
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