Question

What is an equation of the line that passes through the point (-4, 8) and is parallel to the line x + y = 6?

Helppp​

Answer 1

The line x + y = 6 can be written in slope-intercept form (y = mx + b) by solving for y:

y = -x + 6

So the slope of this line is -1.

Since the line we want is parallel to this line, it must also have a slope of -1.

Now we can use the point-slope form of a line to find the equation of the line we want:

y - y1 = m(x - x1)

where m is the slope and (x1, y1) is the given point.

Plugging in the values we know, we get:

y - 8 = -1(x - (-4))

Simplifying:

y - 8 = -x - 4

y = -x + 4

So the equation of the line that passes through the point (-4, 8) and is parallel to the line x + y = 6 is y = -x + 4.