Answer:
0.442 moles
Step-by-step explanation:
To determine the total moles of ions released when 55.1 g of CuSO4 · 5H2O dissolves completely in water, we need to first calculate the number of moles of the compound.
The molar mass of CuSO4 · 5H2O can be calculated as follows:
1 Cu atom x 63.55 g/mol = 63.55 g/mol Cu
1 S atom x 32.06 g/mol = 32.06 g/mol S
4 O atoms x 16.00 g/mol = 64.00 g/mol O
5 H2O molecules x 18.02 g/mol = 90.10 g/mol H2O
Total molar mass = 63.55 + 32.06 + 64.00 + 90.10 = 249.71 g/mol
To calculate the number of moles, we can use the formula:
moles = mass / molar mass
moles = 55.1 g / 249.71 g/mol = 0.221 mol
The compound CuSO4 · 5H2O dissociates into Cu²⁺, SO₄²⁻, and 5H₂O molecules in water. Since each formula unit of CuSO4 · 5H2O produces two ions (one Cu²⁺ ion and one SO₄²⁻ ion), the total number of ions released can be calculated by multiplying the number of moles of the compound by the number of ions produced per mole:
Total moles of ions = 2 ions/mole x 0.221 mol = 0.442 moles of ions
Therefore, when 55.1 g of CuSO4 · 5H2O dissolves completely in water, a total of 0.442 moles of ions are released.