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A gas container is initially at 40.8 mmHg and 88 K. What will the pressure be when the container warms up to 21 C

User Queso
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answer

136.2 mmHg

quick explanation :

P1 / T1 = P2 / T2

P2 = (P1 * T2) / T1

T1 = 88 K = -185.15 °C

T2 = 21 °C + 273.15 = 294.15 K

P2 = (40.8 mmHg * 294.15 K) / (88 K) = 136.2 mmHg

detailed explanation :

Gas pressure calculation.

(P1 * V1) / (T1) = (P2 * V2) / (T2)

P1 = initial pressure

V1 = initial volume (assumed constant)

T1 = initial temperature

P2 = final pressure (what we want to find)

V2 = same as V1 (assumed constant)

T2 = final temperature

T1 = 88 K = -185.15 °C

T2 = 21 °C + 273.15 = 294.15 K

(P1 * V1) / T1 = (P2 * V2) / T2

assuming that the volume of the container remains constant, so V1 = V2

P1 / T1 = P2 / T2

P2 = (P1 * T2) / T1

P2 = (40.8 mmHg * 294.15 K) / (88 K) = 136.2 mmHg

Therefore, the pressure in the container will be 136.2 mmHg when it warms up to 21 °C.

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User Dvo
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