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Tin is widely used for plating steel cans used as food containers, in metals used for bearings, and in solder. What will be the final temperature of a 163.79 g piece of tin that is at an initial temperature of 27.4oC and requires 2432.0 J of heat? The specific heat of tin is 0.226 g/J oC.

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We can use the formula for heat transfer to find the final temperature of the tin:

Q = mcΔT

where Q is the heat transferred, m is the mass of the tin, c is the specific heat of tin, and ΔT is the change in temperature.

We want to solve for ΔT, which we can rearrange as:

ΔT = Q / (mc)

Plugging in the values we know:

m = 163.79 g

c = 0.226 g/J oC

Q = 2432.0 J

ΔT = 2432.0 J / (163.79 g * 0.226 g/J oC)

ΔT = 6.44 oC

Therefore, the final temperature of the tin will be:

Final temperature = Initial temperature + ΔT

Final temperature = 27.4 oC + 6.44 oC

Final temperature = 33.84 oC

So the final temperature of the tin will be 33.84 oC.

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