Question

P4 (s) + 6 H2 (g) → 4 PH3 (g)

Use the balanced equation above.
How many moles of PH3 are produced from 6.59 moles of hydrogen gas?
Type your answer...

Answer 1

Using the balanced chemical equation P4 (s) + 6 H2 (g) → 4 PH3 (g), 4.3933 moles of PH3 are produced from 6.59 moles of hydrogen gas. The proportion based on the mole ratio is used to calculate this.

Step-by-step explanation:

To determine how many moles of PH3 are produced from 6.59 moles of hydrogen gas using the balanced chemical equation P4 (s) + 6 H2 (g) → 4 PH3 (g), we use a mole to mole comparison. According to the equation, 6 moles of H2 produce 4 moles of PH3. To find the moles of PH3 produced from 6.59 moles of H2, we set up a proportion:

(6 moles of H2 / 4 moles of PH3) = (6.59 moles of H2 / x moles of PH3)
Solving for x, we get:
x = (4 moles of PH3 / 6 moles of H2) × 6.59 moles of H2
x = (4/6) × 6.59 moles of PH3
x = 4.3933 moles of PH3
Therefore, 4.3933 moles of PH3 are produced from 6.59 moles of hydrogen gas.

Answer 2

4.39 moles

Step-by-step explanation:

According to the balanced chemical equation:

P4 (s) + 6 H2 (g) → 4 PH3 (g)

6 moles of hydrogen gas (H2) react with 1 mole of phosphorus (P4) to produce 4 moles of phosphine gas (PH3). This means that the mole ratio of H2 to PH3 is 6:4 or 3:2.

To find out how many moles of PH3 are produced from 6.59 moles of H2, we can use the mole ratio as a conversion factor:

6.59 moles H2 x (4 moles PH3 / 6 moles H2) = 4.39 moles PH3

Therefore, 6.59 moles of H2 react to produce 4.39 moles of PH3.