Question

4) An astronaut drops a hammer from 2.0 meters above the surface of the

moon. If the acceleration due to gravity on the moon is 1.62 m/s2, how long
will it take for the hammer to fall to the Moon's surface? (Show your work)

Answer 1

Answer: The time, t, is approximately 1.57 seconds

Step-by-step explanation:

The data we have from the question;

Displacement = 2.0 meters

Acceleration due to gravity on the moon = 1.62

Initial velocity = 0 m/s

We can use the second equation of motion for this one;

S = ut + 1/2at²

Where:

- S is the displacement.

- u is the initial velocity.

- a is the acceleration.

- t is the time measured in seconds.

We are now ready to substitute;

2 = 0(t) + 1/2(1.62)t²

==> 2 = 0 + 0.81t²

==> 2/0.81 = 0.81t²/0.81

==>
`√(2.47)` =
`\sqrt{t ^(2)`

==> The time, t, is approximately 1.57 seconds

Hope this helped! Have a good day :D