Answer:
The balanced chemical equation for the reaction between calcium carbonate (CaCO₃) and hydrochloric acid (HCl) is: CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂.
The molar mass of CaCO₃ is 100.0869 g/mol 1. Therefore, 8.2 g of CaCO₃ is equivalent to 0.0819 moles of CaCO₃.
Since the reaction requires 2 moles of HCl for every mole of CaCO₃, 0.0819 moles of CaCO₃ will require 0.1638 moles of HCl.
The molar mass of HCl is 36.46094 g/mol 2. Therefore, 0.1638 moles of HCl is equivalent to 5.97 g of HCl.
So, you will need approximately 5.97 g of hydrochloric acid (HCl) to react with 8.2 g of calcium carbonate (CaCO₃).
Step-by-step explanation: