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How many moles of O2 are required to react with 19 moles of KCI?

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Answer:

28.5 moles of O2

Step-by-step explanation:

The balanced chemical equation for the reaction between potassium chloride (KCl) and oxygen gas (O2) is:

2 KCl + 3 O2 → 2 KClO3

According to this equation, 2 moles of KCl react with 3 moles of O2 to produce 2 moles of potassium chlorate (KClO3).

Therefore, to determine how many moles of O2 are required to react with 19 moles of KCl, we can use the mole ratio as a conversion factor:

19 moles KCl x (3 moles O2 / 2 moles KCl) = 28.5 moles O2

So, 28.5 moles of O2 are required to react with 19 moles of KCl.

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