Answer:
28.5 moles of O2
Step-by-step explanation:
The balanced chemical equation for the reaction between potassium chloride (KCl) and oxygen gas (O2) is:
2 KCl + 3 O2 → 2 KClO3
According to this equation, 2 moles of KCl react with 3 moles of O2 to produce 2 moles of potassium chlorate (KClO3).
Therefore, to determine how many moles of O2 are required to react with 19 moles of KCl, we can use the mole ratio as a conversion factor:
19 moles KCl x (3 moles O2 / 2 moles KCl) = 28.5 moles O2
So, 28.5 moles of O2 are required to react with 19 moles of KCl.