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If f(x) = 2x^2- 7 and g(x) = 2x + 1, evaluate f(g(x)) when x = -3

User Demarcus
by
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1 Answer

5 votes

Given:-


  • \textsf{f ( x ) = 2x² - 7 }


\:


  • \textsf{g ( x ) = 2x + 1}


\:


  • \textsf{x = -3}


\:

To find:-


  • \textsf{f ( g ( x ) ) = ?}


\:

Solution:-


  • \textsf{f ( x ) = 2x² - 7 * g ( x ) = 2x + 1}


\:


  • \textsf{f ( g ( x ) ) = 2x² - 7 * 2x + 1}


\:

as we know , the value of x is -3 then put it in the equation:


  • \textsf{f ( g ( x ) ) = 2( -3 )² - 7 * 2( -3 )+ 1}


\:


  • \textsf{f ( g ( x ) ) = 2(-9 ) - 7 * -6 + 1}


\:


  • \textsf{f ( g ( x ) ) = -18 - 7 * -6 + 1}


\:


  • \textsf{f ( g ( x ) ) = -25 * -5}


\:


  • \fbox{ \textsf \red{f ( g ( x ) ) = 125 }}


\:

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hope it helps! :)

User Letmecheck
by
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