8.8k views
4 votes
The expression 2x+(x-7)^2 is equivalent to x^2+bx+49 for all values of x.

1 Answer

4 votes

Answer: To see if the expression 2x + (x - 7)^2 is equivalent to x^2 + bx + 49 for all values of x, we can expand the square in the first expression and simplify:

2x + (x - 7)^2 = 2x + (x^2 - 14x + 49)

= x^2 - 12x + 49

Now we can compare this with the second expression, x^2 + bx + 49. Since these two expressions are equivalent for all values of x, their coefficients must be equal. In other words:

x^2 - 12x + 49 = x^2 + bx + 49

Simplifying, we get:

-12x = bx

Dividing both sides by x (note that x cannot be zero because it is in the domain of both expressions), we get:

-12 = b

Therefore, the expression 2x + (x - 7)^2 is equivalent to x^2 - 12x + 49, which is equivalent to x^2 - 12x + 49 for all values of x. The coefficient of x in the second expression is -12, so b = -12.

Explanation:

User Brad Whitaker
by
9.1k points

No related questions found