Question

1.) You have a sample of 1.64 moles of aluminum carbonate is mixed with lithium to produce lithium carbonate and aluminum. How many moles of lithium would completely react with all the aluminum carbonate.

2.) a synthesis reaction between magnesium and nitrogen forms an ionic compound magnesium nitride. If you have 4.226 moles of magnesium how many grams of nitrogen will completely react with the magnesium.

3.) given the following equation 8Fe+S8>8FeS, how many grams FeS are produced, and what mass of iron is needed to react with 16 grams of sulfur

4.) B2H6+3O2>HBO2+2H2O, what mass of O2 will be needed to burn 31.6g B2H6, and how many miles of water are produced from 12.8g B2H6

Answer 1

Step-by-step explanation:

1.) 6Li + Al2(CO3)3 -----> 3Li2CO3 + 2Al

From the stoichiometry of the equation,

6 moles of Li reacts with 1 mole of Al2(CO3)3

x of Li will react with 1.64 moles of Al2(CO3)3

=> x = (1.64 × 6) ÷ 1

=> x = 9.84 moles of Li

2.) 2Mg + N2 -----> 2MgN

2 moles of Mg react completely with 14 g of N2

4.226 moles of Mg will react with x of N2

=> x = (4.226 × 14) ÷ 2

=> x = 29.582 g of N2

3.) 8Fe + S8 -----> 8FeS

256 g of Sulphur give 8(56 + 32)g of FeS

16 g of Sulphur will give x of FeS

=> x = (16 × 704) ÷ 256

=> x = 44 g of FeS

256 g of Sulphur react with 8(56)g of Fe

16 g of Sulphur will react with x of Fe

=> x = (16 × 8 × 56) ÷ 256

=> x = 28 g of Fe

4.) B2H6 + 3O2 -----> HBO2 + 2H2O

27.6 g of B2H6 burn in 3(32)g of O2

31.6 g of B2H6 will burn in x of O2

=> x = (31.6 × 3 × 32) ÷ 27.6

=> x = 109.9 g of O2

27.6 g of B2H6 produce 2 moles of H2O

12.8 g of B2H6 will produce x of H2O

=> x = (12.8 × 2) ÷ 27.6

=> x = 0.93 moles of H2O