Question

A silver-colored necklace with a mass of 43.0 grams is heated in the drying 1 point

oven to a temperature of 120.0c. it is then dropped into a calorimeter
containing 95.0 grams of water at 20.0c. the water and necklace reach a
final temperature of 25.5c. determine, in joules and in calories, how much
energy the water gained. calculate the specific heat of the metal. silver's
specific heat is 0.0558 cal/g.c. was the necklace pure silver? provide an
explanation for your answer. *
your answer

Answer 1

Based on the data provided, the heat gained by water is 2184.05 J and the heat capacity of silver is 0.537 J/g/°C

What is the heat gained by water?

Quantity of heat, H = mcΔT where is massc is heat capacity

ΔT is temperature differenceAlso;Heat gained = heat lost

Heat capacity of water = 4.18 J/g/°C

Heat lost by silver = 43 * c * (120 - 25.5) = 4063.5c

Heat gained by water = 95 * 4.18 * (25.5 -20) = 2184.05 J

from heat lost = heat gained:4063.5c = 2184.05 Jc = 2184.05/4063.5c = 0.537 J/g/°C

Therefore, the heat gained by water is 2184.05 J and the heat capacity of silver is 0.537 J/g/°C

Step-by-step explanation: