Question

I do not understand it can you please give a step by step explanation

If the change in internal energy = 1943J, specific heat capacity = 90J/°C/kg, and temperature change = 41°C, what is the mass of the object?
Give your answer to 2 decimal places.

Answer 1

Answer: The mass of the object is approximately 0.53 kg.

Explanation: We know the formula to calculate the change in internal energy of an object, which is given by ΔU = mcΔT, where ΔU is the change in internal energy, m is the mass of the object, c is the specific heat capacity of the object, and ΔT is the change in temperature.

Here, we have been given the change in internal energy (ΔU = 1943 J), specific heat capacity (c = 90 J/°C/kg), and change in temperature (ΔT = 41°C). Substituting these values in the formula and solving for the mass (m), we get the mass of the object as approximately 0.53 kg.c

We can use the formula for the change in the internal energy of an object:

ΔU = mcΔT

where ΔU is the change in internal energy, m is the mass of the object, c is the specific heat capacity of the object, and ΔT is the change in temperature.

We can rearrange this formula to solve for the mass of the object:

m = ΔU / (c ΔT)

Substituting the given values, we get:

m = 1943 J / (90 J/°C/kg x 41°C)

m = 1943 J / 3690 J/kg

m ≈ 0.53 kg (rounded to 2 decimal places)

Therefore, the mass of the object is approximately 0.53 kg.