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A line has a slope of -2 and passes through the point (6,-16). Write its equation in slope intercept form.

User Oblosys
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1 Answer

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Explanation:

since we have the slope and a point, let's start with the point-slope form first, and then we transform it into the slope-intercept form.

the general slope-intercept form is

y = ax + b

"a" being the slope and b the y-intercept (the y-value when x = 0).

the general point-slope form is

y - y1 = a(x - x1)

"a" is again the slope, (x1, y1) is a point on the line.

so, in our case

y - -16 = -2(x - 6)

y + 16 = -2x + 12

y = -2x - 4

that's it.

User Jessica
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