Question

A 590.0 g brass candlestick has an initial temperature of 98.0°C. If 21100 J of energy is

removed from the candlestick to lower its temperature to 6.8°C, what is the specific heat of
brass?

Answer 1

specific heat of brass is:

c = 0.412 J/g°C

Step-by-step explanation:

We can use the formula:

Q = mcΔT

where Q is the amount of heat transferred, m is the mass of the brass candlestick, c is the specific heat of brass, and ΔT is the change in temperature.

We know the following values:

m = 590.0 g

ΔT = 98.0°C - 6.8°C = 91.2°C

Q = -21100 J (negative sign indicates that heat is being removed)

Substituting these values into the formula, we get:

-21100 J = (590.0 g) c (91.2°C)

Solving for c, we get:

c = -21100 J / (590.0 g * 91.2°C)

c = -0.412 J/g°C

Note that the negative sign on the specific heat value indicates that heat is being removed from the system. We can ignore the sign when reporting the final answer, so the specific heat of brass is:

c = 0.412 J/g°C