Question

Please help me with this

Answer 1

• Length of the hypotenuse is 6.2 mi.

Explanation:

Given,

• Perpendicular (P) = 3.1 mi.
• Base (B) = 5.4 mi

To Find : Hypotenuse

Solution :

Using Pythagoras theorem,

`\sf(Hypotenuse)^2 = (Perpendicular)^2 + (Base) ^2`

On substituting the values we get,

`\longrightarrow (H)^2 = (3.1)^2 + (5.4)^2 \\ \\ \longrightarrow (H)^2 = 9.61 + 29.16 \\ \\ \longrightarrow(H)^2 = 38.77 \\ \\ \longrightarrow H = √(38.77) \\ \\ \longrightarrow H = 6.226`

Therefore, Length of the hypotenuse is 6.2 mi.