Step-by-step explanation:
KOH molarity calculation.
Durga thapaliya Thapaliya
If 6 milliliters of 1M HCl is exactly neutralized by 3 milliliters of KOH, the molarity of the KOH is
a) 1M
b)3M
c)2M
d)9M
The balanced chemical equation for the reaction between HCl and KOH is:
HCl + KOH → KCl + H2O
From the equation, we can see that the mole ratio between HCl and KOH is 1:1. Therefore, the number of moles of HCl in 6 mL of 1M HCl is:
moles of HCl = volume of HCl × concentration of HCl
= 6 mL × 1 mol/L
= 6 × 10^-3 mol
Since the number of moles of HCl is equal to the number of moles of KOH, we can use the following formula to calculate the molarity of KOH:
molarity of KOH = moles of KOH / volume of KOH
We are given that 3 mL of KOH is used to neutralize the HCl. Therefore, the number of moles of KOH is:
moles of KOH = moles of HCl = 6 × 10^-3 mol
Substituting the values in the above formula, we get:
molarity of KOH = moles of KOH / volume of KOH
= 6 × 10^-3 mol / 3 mL
= 2M
Therefore, the molarity of KOH is 2M, and the correct option is (c).