Question

Need help with 1 and 2 in picture

Answer 1

For 1 it would be C for 2 It would be D

Explanation:

Answer 2

ㅤㅤ [ SOLUTION ( 1 ) :- ]

ㅤ

In september, Dorothy sold ::

• ➸ 43 bracelets
• ➸ 12 necklaces
• ➸ For = $1105.25

ㅤ

In october, Dorothy sold ::

• ➸ 74 bracelets
• ➸ 51 necklaces
• ➸ For = $2962.75

ㅤ

Here ::

• ➸ Bracelets = b
• ➸ Necklaces = n

ㅤ

So ::

`\begin{gathered}\begin{gathered}\: \begin{gathered}\begin{gathered} \small{\underline{\boxed{\begin{array}{cc} \\ \: \orange{\frak{(C) \: 43b + 12n = 1105.25}} \\ \\ \orange{\frak{74b + 51n = 2962.75}}\\ \: \end{array}}}} \; \pmb{\bigstar}\end{gathered}\end{gathered}\end{gathered}\end{gathered}`

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ㅤㅤ [ SOLUTION ( 2 ) :- ]

ㅤ

Atq ::

`\begin{gathered}\\:\longmapsto\quad\sf{a + c = 200\qquad\qquad\left\lgroup\begin{matrix}\sf{{eq}^(n)} \: (I) \end{matrix}\right\rgroup} \end{gathered}`

`\begin{gathered}\\:\longmapsto\quad\boxed{\sf{a = 200 - c}}\end{gathered}`

`\begin{gathered}\\:\longmapsto\quad\sf{8a + 6c = 1440\qquad\qquad\left\lgroup\begin{matrix}\sf{{eq}^(n)} \: (II) \end{matrix}\right\rgroup} \end{gathered}`

ㅤ

Substituting the value of (a) in (II) ::

`\begin{gathered} \\ \; \; \sf{:\longmapsto{8(200 - c) + 6c = 1440}} \\ \\ \end{gathered}`

`\begin{gathered} \\ \; \; \sf{:\longmapsto{1600 - 8c + 6c = 1440}} \\ \\ \end{gathered}`

`\begin{gathered} \\ \; \; \sf{:\longmapsto{1600 - 1440 = 8c - 6c}} \\ \\ \end{gathered}`

`\begin{gathered} \\ \; \; \sf{:\longmapsto{160 = 2c}} \\ \\ \end{gathered}`

`\begin{gathered} \\ \; \; \sf{:\longmapsto{\cancel{(160)/(2)} = c}} \\ \\ \end{gathered}`

`\begin{gathered}\\ \; \; :\longmapsto{\boxed{\orange{\frak{c = 80}}}} \; \pmb{\bigstar} \\ \\ \end{gathered}`

Substituting the value of (c) in (II) ::

`\begin{gathered} \\ \; \; \sf{:\longmapsto{a + 80 = 200}} \\ \\ \end{gathered}`

`\begin{gathered} \\ \; \; \sf{:\longmapsto{a = 200 - 80}} \\ \\ \end{gathered}`

`\begin{gathered}\\ \; \; :\longmapsto{\boxed{\orange{\frak{a = 120}}}} \; \pmb{\bigstar} \\ \\ \end{gathered}`

∴ 120 Adult Tickets Were Sold

`\bf{\pmb{\underline{\rule{170pt}{5pt}}}}`