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ASAP!! ITS URGENT

Find the lateral area, total area, and volume of each right circular come.

ASAP!! ITS URGENT Find the lateral area, total area, and volume of each right circular-example-1

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Answer:

58.


135\pi \: {km}^(2)

59.


216\pi \: {km}^(2)

60.


324 \: {km}^(3)

61.


72 √(5 ) \pi \: {m}^(2)

62.


72( √(5) + 2)\pi \: {m}^(2)

63.


240\pi \: {m}^(3)

Explanation:

58. First, we have to find the length of the cone shaper by using the Pythagorean theorem:


{l}^(2) = {12}^(2) + {9}^(2) = 144 + 81 = 225


l > 0


l = √(225) = 15 \: km

Now, let's find the lateral surface (r = 9 km):


a(lateral) = \pi * r * l = \pi * 9 * 15 = 135\pi \: {km}^(2)

59. The area of total surface is equal to a lateral surface's and base surface's sum:

Let's find the area of the base first:


a(base) = \pi * {r}^(2) = {9}^(2) * \pi = 81\pi \: {km}^(2)

Now, let's find the area of total surface:


a(total) = 135\pi + 81\pi = 216\pi\: {km}^(2)

60. h = 12 km


v = (1)/(3) * a(base) * h = (1)/(3) * 81\pi * 12 = 324\pi \: {km}^(3)

61. r = 12m

h = 5m

Let's find the length of the cone shaper by using the Pythagorean theorem:


{l}^(2) = {12}^(2) + {6}^(2) = 144 + 36 = 180


l > 0


l = √(180) = 6 √(5) \: m

Now, let's find the area of the lateral surface:


a(lateral) = \pi * r * l = \pi * 12 * 6 √(5) = 72 √(5) \pi \: {m}^(2)

62.


a(base) = \pi * {r}^(2) = 144\pi \: {m}^(2)


a(total) = 72 √(5) \pi + 144\pi = 72( √(5) + 2)\pi \: {m}^(2)

63.


v = (1)/(3) * a(base) * h = (1)/(3) * 144\pi * 5 = 240\pi \: {m}^(3)

I don't know if these answer are correct, though...

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