Question

ASAP!! ITS URGENT

If the perimeter of a rhombus is 52 m and one diagonal is 24 m, find its area.

Answer 1

120m²

Explanation:

Let the side be x

perimeter of a rhombus=

4*side=4x=52m

x=52/4= 13m (dividing both sides by x)

We know that the diagonals of a rhombus bisect each other at right angles.

Let the intersecting point of diagonals be O.

Consider triangle AOB

OA=24/2=12m

OB=√(AB²-OA²)=√(13²-12²)

=√(169-144)=√25=5m

Then length of other diagonal

BD=2*OB=2*5=10m

Area of the rhombus

=1/2*AC*BD=1/2*24*10=120m²