Answer:
120m²
Explanation:
Let the side be x
perimeter of a rhombus=
4*side=4x=52m
x=52/4= 13m (dividing both sides by x)
We know that the diagonals of a rhombus bisect each other at right angles.
Let the intersecting point of diagonals be O.
Consider triangle AOB
OA=24/2=12m
OB=√(AB²-OA²)=√(13²-12²)
=√(169-144)=√25=5m
Then length of other diagonal
BD=2*OB=2*5=10m
Area of the rhombus
=1/2*AC*BD=1/2*24*10=120m²