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Please help, trigonometry 9th grade
tysm

Please help, trigonometry 9th grade tysm-example-1
User Quirijn
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1 Answer

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Part a:

Let's express this as a fraction, where the rise is the numerator and the run is the denominator. The rise is 1 unit of height, and the run is 10 units of distance. Therefore, the gradient can be expressed as: 1/10

To find the angle that the road makes with the horizontal using trigonometry is: tan θ = 1/10

Solving for θ, we get:

θ = tan^(-1)(1/10) ≈ 5.7 degrees

Therefore, the road makes an angle of approximately 5.7 degrees with the horizontal.

Part b:

If the car drives 2 km along the road, we can use the angle calculated in part a to find the vertical height that the car has climbed. We know that the distance covered along the road is the run, which is 2 km or 2000 meters.

Using trigonometry again, we can find the vertical height climbed by the car, which is the opposite side. The tangent of the angle is: tan θ = 1/10

Let's rearrange this to solve for the opposite side, which is the vertical height climbed:

opposite side = adjacent side x tan θ

opposite side = 2000 x tan (5.7 degrees)

opposite side ≈ 200 meters

Therefore, the car has climbed approximately 200 meters vertically along the inclined road.

User Etan
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