Question

QUICK PLEASE!!!!!

Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a radius of 4 feet and a height of 10 feet. Container B has a radius of 3 feet and a height of 18 feet. Container A is full of water and the water is pumped into Container B until Container A is empty. To the nearest tenth, what is the percent of Container B that is full after the pumping is complete?

Answer 1

Explanation:

The volume of a cylinder is given by the formula V = πr^2h, where r is the radius and h is the height.

Container A has a volume of V_A = π(4^2)(10) = 160π cubic feet.

Container B has a volume of V_B = π(3^2)(18) = 162π cubic feet.

When the water is transferred from Container A to Container B, the volume of water transferred is equal to the volume of Container A, which is 160π cubic feet.

The volume of water in Container B after the transfer is V_B' = V_A + V_B = 160π + 162π = 322π cubic feet.

The percent of Container B that is full after the transfer is (V_B' / V_B) x 100%.

Substituting the values we have:

(V_B' / V_B) x 100% = (322π / 162π) x 100% = 198.77%

Rounding this to the nearest tenth, we get that Container B is approximately 198.8% full after the transfer. However, since this value is greater than 100%, we can conclude that Container B is completely full, and there is an additional 98.8% of its volume that is empty.