218k views
5 votes
QUICK PLEASE!!!!!

Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a radius of 4 feet and a height of 10 feet. Container B has a radius of 3 feet and a height of 18 feet. Container A is full of water and the water is pumped into Container B until Container A is empty. To the nearest tenth, what is the percent of Container B that is full after the pumping is complete?

User Rosstex
by
8.6k points

1 Answer

1 vote

Explanation:

The volume of a cylinder is given by the formula V = πr^2h, where r is the radius and h is the height.

Container A has a volume of V_A = π(4^2)(10) = 160π cubic feet.

Container B has a volume of V_B = π(3^2)(18) = 162π cubic feet.

When the water is transferred from Container A to Container B, the volume of water transferred is equal to the volume of Container A, which is 160π cubic feet.

The volume of water in Container B after the transfer is V_B' = V_A + V_B = 160π + 162π = 322π cubic feet.

The percent of Container B that is full after the transfer is (V_B' / V_B) x 100%.

Substituting the values we have:

(V_B' / V_B) x 100% = (322π / 162π) x 100% = 198.77%

Rounding this to the nearest tenth, we get that Container B is approximately 198.8% full after the transfer. However, since this value is greater than 100%, we can conclude that Container B is completely full, and there is an additional 98.8% of its volume that is empty.

User Odrade
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories