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An 18 wheel truck weighs 15 000 kg. The combined area of all tires touching the ground is 0.8 m2. How much pressure does ONE tire exert on the ground? (Remember: 1 kg = 9.8 N; 1 N/m2 = 1 Pa; 1000 Pa = 1kPa)

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Answer:

10.208 kPa

Step-by-step explanation:

The weight of the truck is 15,000 kg, which can be converted to Newtons using the conversion factor 1 kg = 9.8 N:

Weight of the truck = 15,000 kg × 9.8 N/kg = 147,000 N

The area of all tires touching the ground is 0.8 m².

The pressure exerted by one tire on the ground can be calculated using the formula:

pressure = force / area

where force is the weight of the truck divided by the number of tires (18), and area is the combined area of all tires touching the ground (0.8 m²).

So, the pressure exerted by one tire can be calculated as follows:

force per tire = weight of the truck / number of tires

force per tire = 147,000 N / 18 = 8,166.67 N

pressure = force per tire / area

pressure = 8,166.67 N / 0.8 m² = 10,208.33 Pa

Finally, we can convert this pressure to kilopascals (kPa) by dividing by 1000:

pressure = 10,208.33 Pa / 1000 = 10.208 kPa

Therefore, one tire of the 18 wheel truck exerts a pressure of 10.208 kPa on the ground.

User Vineet Bhatia
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