Question

3. PHYSICS Suppose you are traveling in a car when a beam of light passes from the air to the windshield. The measure of the angle of incidence 0; is 55°, and the measure of the angle of refraction 0, is 35.25⁰. sin i Use Snell's Law, = n, to find the index of sin Or refraction n of the windshield to the nearest thousandth​

Answer 1

Snell's Law states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the indices of refraction of the two media:

sin i / sin r = n2/n1

where i is the angle of incidence, r is the angle of refraction, n1 is the index of refraction of the initial medium (in this case air), and n2 is the index of refraction of the second medium (in this case the windshield).

We can rearrange Snell's Law to solve for n2:

n2 = n1 * sin i / sin r

Plugging in the given values, we have:

n2 = 1.0003 * sin 55° / sin 35.25°

Using a calculator, we get:

n2 ≈ 1.526

Therefore, the index of refraction of the windshield is approximately 1.526 to the nearest thousandth.