Answer:
a) P(Both) = 7/75
b) P(B&~S) = 1/5
c) P(~B&~S) = 4/15
d) P(~Both) = 68/75
Explanation:
First, the 40 subway riders includes SubwayOnly people and also Subway&Bus...BOTH people.
Likewise, 22 bus people are BusOnly people as well as Bus&Subway--BOTH people.
So there is some overlap and we should sort that out before writing these probabilities. Let's use a Venn diagram.
40+22 is 62, but we know theres only 55 public transportation people. 62-55 is 7. Thats the overlap. There are 7 people who ride BOTH bus and subway. We put them in the middle and subtract to find the BusOnly and SubwayOnly people.
40 -7 is 33 SubwayOnly people.
22 - 7 is 15 BusOnly people.
55 people ride some public transpo, so 75 - 55 is 20 who people ride nothing (so cars or walkers).
Now we can write probabilities.
a) BOTH is 7/75
b) BusOnly is 15 people so probability is 15/75, which can be reduced so 15/75 = 1/5
c) NoBus and NoSub people are the 20 car or walkers. 20/75 = 4/15
NotBOTH people are the 20 (car/walkers) also the BusOnly and SubwayOnly. Thats 20+33+15, 68 people. Another way to think of it is ALL - 7 =
75 - 7 =
68 people, so the probability is 68/75.
also see image.