Answer:
The balanced chemical equation for the reaction between nitrogen gas and hydrogen gas to produce ammonia gas is:
N2 + 3H2 → 2NH3
From the equation, we can see that 3 moles of hydrogen gas are required to react with 1 mole of nitrogen gas to produce 2 moles of ammonia gas.
To find the volume of hydrogen gas required to react with 10.0 g of nitrogen gas at STP, we can use the following steps:
1. Convert the mass of nitrogen gas to moles:
moles of N2 = mass / molar mass
moles of N2 = 10.0 g / 28.0 g/mol
moles of N2 = 0.357 mol
2. Use the mole ratio from the balanced equation to find the moles of hydrogen gas required:
moles of H2 = 3 x moles of N2
moles of H2 = 3 x 0.357 mol
moles of H2 = 1.07 mol
3. Use the ideal gas law to find the volume of hydrogen gas at STP:
PV = nRT
where P = 1 atm, V is the volume we want to find, n = moles of gas, R = 0.0821 L·atm/mol·K (the gas constant), and T = 273 K (standard temperature at STP).
Rearranging the equation to solve for V, we get:
V = nRT / P
V = 1.07 mol x 0.0821 L·atm/mol·K x 273 K / 1 atm
V = 24.5 L
Therefore, the volume of hydrogen gas required to react with 10.0 g of nitrogen gas at STP is 24.5 L.