Question

The rate constant for the first-order decomposition at 45 degree C of dinitrogen pentoxide, N2O5, dissolved in chloroform, CHCI3, is 6.2*10^-4 min^-1. What is the rate of the reaction when [N2O5]=0.40 M? 2N2O5 -> 4NO2 + O2?

Answer 1

The rate law for a first-order reaction is:

rate = k[N2O5]

where k is the rate constant and [N2O5] is the concentration of N2O5.

Plugging in the values given:

rate = (6.2*10^-4 min^-1) * (0.40 M) = 2.48*10^-4 M/min

Therefore, the rate of the reaction when [N2O5]=0.40 M is 2.48*10^-4 M/min.