Answer:
The rate law for a first-order reaction is:
rate = k[N2O5]
where k is the rate constant and [N2O5] is the concentration of N2O5.
Plugging in the values given:
rate = (6.2*10^-4 min^-1) * (0.40 M) = 2.48*10^-4 M/min
Therefore, the rate of the reaction when [N2O5]=0.40 M is 2.48*10^-4 M/min.