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Solve for x. Round to the nearest tenth.

x =


(40 points)

Solve for x. Round to the nearest tenth. x = (40 points)-example-1

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Answer:


  • x = 18.5

Explanation:

To find:-

  • The value of "x" .

Answer:-

We are given a right angled triangle, in which two legs viz perpendicular and base are x and 15 , and one of the angles is 51° .

With respect to 51° ,

  • 15 is base .
  • x is perpendicular .

Also , in a right angled triangle, tangent is defined as the ratio of perpendicular and base. So ,


\implies \tan\theta =(p)/(b) \\

On substituting the respective values, we have;


\implies \tan\theta =(x)/(15)\\

  • Value of theta is 51° , so that ;


\implies \tan51^o = (x)/(15) \\

  • Value of tan51° is approximately 1.2349 .


\implies 1.2349 =(x)/(15) \\

Cross multiply,


\implies x = 15\cdot 1.2349 \\

Simplify,


\implies x = 18.5235 \\

Rounding off to nearest tenth will give us,


\implies \boxed{ x = 18.5 } \\

Hence the value of x is 18.5 ( nearest tenth) .

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