What is the resistance of a 150 W light bulb running on a 120 V circuit

asked Nov 14, 2024 140k views

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Answer:

96 Ω

Step-by-step explanation:

Given:

U = 120 V

P = 150 W

Find: R - ?

$r = \frac{ {u}^(2) }{p}$

$r = \frac{ {120}^(2) }{150} = 96 \: Ω$

Haruka answered Nov 19, 2024

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