Answer: 50%
Explanation: Blood type is inherited from both parents. The ABO blood type is controlled by a single gene (the ABO gene) with three types of alleles inferred from classical genetics: i, IA, and IB1. The i allele codes for no antigen on the red blood cells, the IA allele codes for the A antigen, and the IB allele codes for the B antigen. The IA and IB alleles are codominant, meaning that they both express their antigens when present together. The i allele is recessive, meaning that it is masked by the presence of either IA or IB.
A person’s blood type is determined by the combination of alleles they inherit from their parents. For example, a person with blood type A can have either IAIA or IAi as their genotype. A person with blood type B can have either IBIB or IBi as their genotype. A person with blood type AB can have only IAIB as their genotype. A person with blood type O can have only ii as their genotype.
In this question, the man has blood type B and his parents had blood type O. This means that his genotype must be IBi, since he inherited one i allele from each parent and one IB allele from a mutation or a rare case of non-paternity. The woman has blood type AB, which means that her genotype is IAIB.
To find the percentage of their child having blood type B, we can use a Punnett square to show the possible combinations of alleles from each parent. A Punnett square is a diagram that shows the possible outcomes of a genetic cross.
A Punnett square is a way of showing the possible combinations of alleles that can result from a genetic cross between two parents. Each parent contributes one allele for each gene to their offspring. The alleles are represented by letters, such as IA, IB, or i for the ABO blood type gene. The letters are arranged in rows and columns to show the possible combinations.
To make a Punnett square, we first write the alleles of one parent along the top of the square, and the alleles of the other parent along the left side of the square. For example, if one parent has IA and IB alleles, we write IA and IB along the top. If the other parent has IB and i alleles, we write IB and i along the left side.
Then, we fill in each box of the square by combining the alleles from each parent. For example, the box in the top left corner is filled by combining IA from the top parent and IB from the left parent. This gives us IAIB as the genotype for that box. We repeat this process for each box until we have filled in all four boxes.
The Punnett square shows us the possible genotypes and phenotypes of the offspring. The genotype is the combination of alleles that an individual has for a gene. The phenotype is the observable trait that results from the genotype. For example, IAIB is a genotype that results in blood type AB as a phenotype.
The Punnett square also shows us the probability of each genotype and phenotype occurring in the offspring. The probability is calculated by dividing the number of boxes with a certain genotype or phenotype by the total number of boxes. For example, there are two boxes with blood type B (IBIB and IBi) out of four boxes total. Therefore, the probability of blood type B is 2/4 or 50%. We can do this for each genotype and phenotype to find their probabilities.
Hope this helps, and have a great day! =)