Question

Lesson 5 Practice Problems 1. The solution to a system of equations is (6, -3). Choose two equations that might make up the system. A. y = -3x+6 B.y=2x-9 C. y = -5x + 27 D. y = 2x - 15 E. y = -4x + 27 (From Unit 4, Lesson 13.)​

Answer 1

Answer is C). And D).

Answer 2

C and D

Explanation:

Substitute 6 for x and -3 for y.

C:

y = -5x + 27 (6,-3)

-3 = -5(6) + 27

-3 = -30 + 27

-3 = -3 check

D:

y = 2x - 15 (6, -3)

-3 = 2(6) - 15

-3 = 12 - 15

-3 = -3 Checks.

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