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ΔABC has coordinates of A (–6, –3), B (7, –7), and C (0, 3). Find the coordinates of its image after a dilation centered at the origin with a scale factor of 1.5.

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Answer:

A(-9, -4.5), B(10.5, -10.5), and C(0, 4.5)

Explanation:

To find the coordinates of the image of triangle ABC after a dilation centered at the origin with a scale factor of 1.5, we need to multiply the coordinates of each point by 1.5.

The coordinates of point A after dilation can be found by multiplying its x-coordinate and y-coordinate by 1.5:

x-coordinate of A after dilation = 1.5 × (-6) = -9

y-coordinate of A after dilation = 1.5 × (-3) = -4.5

So the coordinates of point A after dilation are (-9, -4.5).

Similarly, we can find the coordinates of points B and C after dilation:

x-coordinate of B after dilation = 1.5 × 7 = 10.5

y-coordinate of B after dilation = 1.5 × (-7) = -10.5

Coordinates of point B after dilation are (10.5, -10.5).

x-coordinate of C after dilation = 1.5 × 0 = 0

y-coordinate of C after dilation = 1.5 × 3 = 4.5

Coordinates of point C after dilation are (0, 4.5).

Therefore, the coordinates of the image of triangle ABC after a dilation centered at the origin with a scale factor of 1.5 are:

A(-9, -4.5), B(10.5, -10.5), and C(0, 4.5)

User Royce Raju Beena
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